x^2-15x-2200=0

Solution for x^2-15x-2200=0 equation:

x^2-15x-2200=0

a = 1; b = -15; c = -2200;
Δ = b2-4ac
Δ = -152-4·1·(-2200)
Δ = 9025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9025}=95$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-95}{2*1}=\frac{-80}{2}
=-40
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+95}{2*1}=\frac{110}{2}
=55
$